1 条题解

  • 0
    @ 2025-1-12 18:25:08
    #include <iostream>
    #include <vector>
    #include <cmath>
    
    using namespace std;
    
    int main() {
    	int n;
    	cin >> n;
    	
    	int X, Y, R;
    	cin >> X >> Y >> R;
    	
    	vector<pair<int, int>> points(n);
    	for (int i = 0; i < n; ++i) {
    		cin >> points[i].first >> points[i].second;
    	}
    	
    	int count = 0;
    	for (int i = 0; i < n; ++i) {
    		int x = points[i].first;
    		int y = points[i].second;
    		double distance = sqrt((x - X) * (x - X) + (y - Y) * (y - Y));
    		if (distance <= R) {
    			count++;
    		}
    	}
    	
    	cout << count << endl;
    	
    	return 0;
    }
    

    信息

    ID
    104
    时间
    1000ms
    内存
    64MiB
    难度
    9
    标签
    递交数
    8
    已通过
    8
    上传者