3 条题解

  • 0
    @ 2025-1-10 17:03:59
    #include <bits/stdc++.h>
    using namespace std;
    
    const int N = 101;
    
    int main() {
        int n;
        cin >> n;
    
        for (int i = 0; i < n; ++i) {
            string S1, S2;
            cin >> S1 >> S2;
    
            if (S1 == S2) {
                cout << "Tie" << endl;
            }
            else if ((S1 == "Rock" && S2 == "Scissors") ||
                (S1 == "Scissors" && S2 == "Paper") ||
                (S1 == "Paper" && S2 == "Rock")) {
                cout << "Player1" << endl;
            }
            else {
                cout << "Player2" << endl;
            }
        }
    
        return 0;
    }
    #include <bits/stdc++.h>
    using namespace std;
    
    const int N = 101;
    
    int main() {
        int n;
        cin >> n;
    
        for (int i = 0; i < n; ++i) {
            string S1, S2;
            cin >> S1 >> S2;
    
            if (S1 == S2) {
                cout << "Tie" << endl;
            }
            else if ((S1 == "Rock" && S2 == "Scissors") ||
                (S1 == "Scissors" && S2 == "Paper") ||
                (S1 == "Paper" && S2 == "Rock")) {
                cout << "Player1" << endl;
            }
            else {
                cout << "Player2" << endl;
            }
        }
    
        return 0;
    }
    //🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯🌯
    
    
    • 0
      @ 2025-1-10 17:00:03
      #include <bits/stdc++.h>
      using namespace std;
      
      const int N = 101;
      
      int main() {
          int n;
          cin >> n;
      
          for (int i = 0; i < n; ++i) {
              string S1, S2;
              cin >> S1 >> S2;
      
              if (S1 == S2) {
                  cout << "Tie" << endl;
              }
              else if ((S1 == "Rock" && S2 == "Scissors") ||
                  (S1 == "Scissors" && S2 == "Paper") ||
                  (S1 == "Paper" && S2 == "Rock")) {
                  cout << "Player1" << endl;
              }
              else {
                  cout << "Player2" << endl;
              }
          }
      
          return 0;
      }
      \\逼哥抄袭 菜就多练!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
      
      • 0
        @ 2025-1-10 16:58:07
        #include <bits/stdc++.h>
        using namespace std;
        
        const int N = 101;
        
        int main() {
            int n;
            cin >> n;
        
            for (int i = 0; i < n; ++i) {
                string S1, S2;
                cin >> S1 >> S2;
        
                if (S1 == S2) {
                    cout << "Tie" << endl;
                }
                else if ((S1 == "Rock" && S2 == "Scissors") ||
                    (S1 == "Scissors" && S2 == "Paper") ||
                    (S1 == "Paper" && S2 == "Rock")) {
                    cout << "Player1" << endl;
                }
                else {
                    cout << "Player2" << endl;
                }
            }
        
            return 0;
        }
        
        
        • 1

        信息

        ID
        1293
        时间
        1000ms
        内存
        128MiB
        难度
        3
        标签
        递交数
        31
        已通过
        20
        上传者